13v^2-7100v-420000=0

Solution for 13v^2-7100v-420000=0 equation:

13v^2-7100v-420000=0

a = 13; b = -7100; c = -420000;
Δ = b2-4ac
Δ = -71002-4·13·(-420000)
Δ = 72250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{72250000}=8500$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7100)-8500}{2*13}=\frac{-1400}{26}
=-53+11/13
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7100)+8500}{2*13}=\frac{15600}{26}
=600
$